2/5x-4x^2=0

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Solution for 2/5x-4x^2=0 equation: 


x in (-oo:+oo)

(2/5)*x-(4*x^2) = 0

(2/5)*x-4*x^2 = 0

2/5*x-4*x^2 = 0

DELTA = (2/5)^2-(-4*0*4)

DELTA = 4/25

DELTA > 0

x = ((4/25)^(1/2)-2/5)/(-4*2) or x = (-(4/25)^(1/2)-2/5)/(-4*2)

x = 0 or x = 1/10

x in { 0, 1/10 }

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